^{0} & 60^{0} respectively. Find the width of the river and the hight of the other temple.

Dear Student!

Here is the answer to your query.

Let AB and CD be the two temples and BC be the width of the river.

Then ∠ ADE = 30° and ∠ ACB = 60°

**Given :** AB = 50 m

In Δ ABC

In Δ AED

Hence the width of the river is 28.867 m and height of the other temple is 33.33 m

Cheers!

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