Q1)

*Use the following information to answer the next question.*

Two plane mirrors, M_{1} and M_{2} are placed at a right angle. A ray of light is incident on M_{1} at P_{1}and gets reflected from M_{1}. It then gets reflected from M_{2} at P_{2}.

If OP_{1} = OP_{2}, then the angle of reflection of the ray at P_{2} will be

kindly explain this question to me in simple and easy language

The angle of reflection is always equal to the angle of incidence. Let*i*be the angle of incidence at P_{1}on mirror M_{1}. The following figure shows the various angles the light ray makes with the mirrors, M_{1}and M_{2}.

Since M_{1}OM_{2}is 90, the normal XP_{1}on M_{1}is parallel to M_{2}.

Therefore, XP_{1}P_{2}= P_{1}P_{2}O =*i*

Since P_{1}O = OP_{2}, OP_{1}P_{2}= OP_{2}P_{1}=*i*

∴90 *i*=*i*

2*i*= 90

∴*i*= 45

Since 90 *i*= 90 45 = 45, all the angles will be 45. Hence, all the reflected and the incident angles will be 45

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