Q5 The value of 3+log3422+12log(494)+13log(1125) is - Maths - Mathematical Reasoning

Question

Q 5   T h e   v a l u e   o f   3 + log 342 2 +
1 2 log ( 49 4 ) + 1 3 log ( 1 125 )   i s

Neha Sethi · Accepted Answer

Dear student
Assuming the base as 10
We have3+log103432+12log10494+13log101125=3+log10732+log1072212+log1015313=3+3log1072+log1072+log1015=31+log1072+log107-log102+log101-log105=31+log1072+log107-log102-log10102=31+log1072+log107-log102-log1010+log102=31+log1072+log107-1=31+log1071+log107=3Note:logmn=nlogmlogmn=logm-lognlog1=0
Regards

Q 5 T h e v a l u e o f 3 + log 342 2 + 1 2 log ( 49 4 ) + 1 3 log ( 1 125 ) i s

$Q 5 T h e v a l u e o f \frac{3 + \log 342}{2 + \frac{1}{2} \log (\frac{49}{4}) + \frac{1}{3} \log (\frac{1}{125})} i s$