Question 15 and Question 16 i] questikn please help me and answer it as soon.as possib?e.

Question 15 and Question 16 i] questikn please help me and answer it as soon.as possib?e. ltk•lhi 19991 is mid• in (if') sin sinA sinA —2 Sin: A.

Dear Student,

Q 15.

4sinA=3 cosAsinAcosA=34tanA=34Length of perpendicular= 3 units and length of base=4 unitsUsing pythagoras theorem,hypotenuse=32+42 = 5 unitsNow sinA=PerpendicularHypotenuse= 35Similarly, CosA=BaseHypotenuse=45Now, 5 sinA+5 cosA = 5×35+5×45 = 7
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