Dear Student, Answer 6:The five pairs of integers (a,b) such that a÷b = -3 can be:(-15,5) ⇒-15÷5 = -3(-12,4) ⇒-12÷4 = -3(18,-6) ⇒18÷-6 = -3(300,-100) ⇒300÷-100 = -3(-54,18) ⇒-54÷18 = -3 Please post the remaining queries in separate threads so that we can help you as soon as possible Regards

Question 6 and 7.

Question 6 and 7. five pairs —3. The at uaril at tcmFracurc x End-night? EXEMPLAR PROBLEMS _ The in the -62. —37.—12, — . The value of S does not lie between: (b) 0 and 10 (ai O and —10 When divide a negative integer by a integer. we And a sign before quotient

Dear Student,

A n s w e r 6 : T h e f i v e p a i r s o f i n t e g e r s (a, b) s u c h t h a t a \div b = - 3 c a n b e : (- 15, 5) \Rightarrow - 15 \div 5 = - 3 (- 12, 4) \Rightarrow - 12 \div 4 = - 3 (18, - 6) \Rightarrow 18 \div - 6 = - 3 (300, - 100) \Rightarrow 300 \div - 100 = - 3 (- 54, 18) \Rightarrow - 54 \div 18 = - 3

Please post the remaining queries in separate threads so that we can help you as soon as possible.

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Question 6 and 7. Question 6 and 7. five pairs —3. The at uaril at tcmFracurc x End-night? EXEMPLAR PROBLEMS _ The in the -62. —37.—12, — . The value of S does not lie between: (b) 0 and 10 (ai O and —10 When divide a negative integer by a integer. we And a sign before quotient

Question 6 and 7.

Question 6 and 7. five pairs —3. The at uaril at tcmFracurc x End-night? EXEMPLAR PROBLEMS _ The in the -62. —37.—12, — . The value of S does not lie between: (b) 0 and 10 (ai O and —10 When divide a negative integer by a integer. we And a sign before quotient