Question no.6

Question no.6 FINDING THE VALuE OF AN ALGEBRAIC EXPRESSION and

Dear Student,
subtarct 2a+3b ,a-2b+c, -a+2c and 4a+2b-5 from 6a-4b+8Solution :First adding 2a+3b ,a-2b+c, -a+2c and 4a+2b-5we get        2a+3b         a-2b+c     -a         +2c       4a+2b         -5+___________________       6a+3b+3c-5 Now subtact   6a+3b+3c-5 from 6a-4b+8 =    6a-4b+8-  6a+3b+3c-5   =6a-4b+8-6a-3b-3c+5=-7b-3c+13Answer     
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-3+13-3c
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