Question Number 20 please! :)
Dear Student,
Power of the electric iron (P) = 2 kW
Time for which the iron is operated daily (t) = 3 h
Daily energy consumption (Edaily) = P × t
= 2 kW × 3 h
= 6 kWh
Total energy consumed in one week (Eweek) = 7 × Edaily
= 7 × 6
= 42 kWh
Total cost = Rs. 4.25 × Eweek
= Rs. 4.25 × 42
= Rs. 178.5
Regards
Power of the electric iron (P) = 2 kW
Time for which the iron is operated daily (t) = 3 h
Daily energy consumption (Edaily) = P × t
= 2 kW × 3 h
= 6 kWh
Total energy consumed in one week (Eweek) = 7 × Edaily
= 7 × 6
= 42 kWh
Total cost = Rs. 4.25 × Eweek
= Rs. 4.25 × 42
= Rs. 178.5
Regards