Question of salt analysis :
For nitrate test : sample salt + conc. H2SO4 ; adding Cu pellets will result in formation of brown gas which shows presence of nitrate ion.
Reactions : NO3 - + H2SO4 == HSO4 - + HNO3
4 HNO3 + Cu == Cu(NO3) + 2 NO2 (brown gas) + 2 H2O

Why this reaction won't follow if dilute H2SO4 were used instead of conc. H2SO4 ?

Concentrated sulphuric acid reacts with the nitrate ion to form nitric acid. Nitric acid  then reacts with the copper turning forms nitrogen monoxide. Nitrogen monoxide is further oxidized to nitrogen dioxide. Dilute sulphuric acid cannot remove completely nitrate ion from the salt. Only partial removal occur. The complete formation of nitric acid is needed as it acts as an oxidising agent too.

  • 2
What are you looking for?