Question:
Two men and a women are entrusted with a task. The second man needs three hours more to cope with the job than the first man and the women would need working together. The first man, working alone, would need as much time as the second man and the woman working together. The first man, working alone, would spend eight hours less than the double period of time the second man would spend working alone. How much time would the two men and the woman need to complete the task if they all worked together? 

Dear student,


2×ta+3-ta=8                --[using (1)]2ta+6-ta=8ta+6=8ta=8-6ta=2 hoursNow B and woman together take 2 hours and A also take 2 hours, so time required will be half when all 3 work together. So in 1 hourwork would be completed.

Regards

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