rank of word papad in dictionary

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Please find below the solution to the asked query:

$$\begin{gathered} \mathrm{Given} \mathrm{word} \mathrm{is} \mathrm{papad} \\ \mathrm{Words} \mathrm{beginning} \mathrm{with} \mathrm{a} \\ \mathrm{a\_}\hspace{0.17em}\mathrm{\_}\hspace{0.17em}\mathrm{\_}\hspace{0.17em}\mathrm{\_} \\ \mathrm{remaining} \mathrm{words} \mathrm{a},\mathrm{p},\mathrm{p},\mathrm{d} \\ \mathrm{no}. \mathrm{of} \mathrm{arrangements}:=\frac{4!}{2!}=\frac{24}{2}=12 \\ \mathrm{Words} \mathrm{beginning} \mathrm{with} \mathrm{d} \\ \mathrm{d\_}\hspace{0.17em}\mathrm{\_}\hspace{0.17em}\mathrm{\_}\hspace{0.17em}\mathrm{\_} \\ \mathrm{remaining} \mathrm{words} \mathrm{a},\mathrm{a},\mathrm{p},\mathrm{p} \\ \mathrm{no}. \mathrm{of} \mathrm{arrangements}:=\frac{4!}{2!2!}=\frac{24}{4}=6 \\ \mathrm{Words} \mathrm{beginning} \mathrm{with} \mathrm{p} \\ \mathrm{paa}\hspace{0.17em}\hspace{0.17em}\mathrm{\_}\hspace{0.17em}\mathrm{\_} \\ \mathrm{remaining} \mathrm{words} ,\mathrm{p},\mathrm{d} \\ \mathrm{no}. \mathrm{of} \mathrm{arrangements}:=2!=2 \\ 12+6+2=20 \mathrm{words} \\ \mathbf{next}\mathbf{ }\mathbf{word}\mathbf{:}\mathbf{papad}\mathbf{ }\mathbf{=}\mathbf{ }\mathbf{21}\mathbf{st}\mathbf{ }\mathbf{words} \end{gathered}$$

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