Reduce the equation of the straight line 3x + 4y + 15 = 0 to normal form and find the - Maths - Straight Lines

Question

Reduce the equation of the straight line 3x + 4y + 15 = 0 to normal
form and find the perpendicular distance of the line from the
origin?

Manbar Singh · Accepted Answer

The given equation of line is,    3x + 4y + 15 = 0⇒3x + 4y = -15⇒-3x  -4y = 15    
1Now, coefficient of x2 + coefficient of y2 = 9+16 = 5Now, dividing both sides of 1 by coefficient of x2 + coefficient of y2, we get-3x5 - 4y5 = 3This is the required normal form of the given equation
Now, length of ⊥ drawn from the origin to it is 3 units

Reduce the equation of the straight line 3x + 4y + 15 = 0 to normal form and find the perpendicular distance of the line from the origin?