(secA-tanA)2= cosecA-1/cosecA+1 Share with your friends Share 0 Ashutosh Verma answered this Answer : Prove that : Sec A - tan A 2 = Cosec A - 1Cosec A + 1 Taking LHS : Sec A - tan A 2 ⇒ Sec2 A + tan2 A - 2Sec A tan A ⇒ 1Cos2 A + Sin 2ACos2 A - 2× 1Cos A× Sin ACos A⇒ 1Cos2 A + Sin 2ACos2 A - 2 Sin ACos2 A ⇒ 1 +Sin 2A - 2 Sin ACos2 A ⇒ Sin A - 1 21 - Sin 2 A ⇒ 1 - Sin A 21 - Sin A1 + Sin A ⇒ 1 - Sin A 1 + Sin A ⇒ 1 -1 Cosec A 1 + 1 Cosec A ⇒ Cosec A - 1 Cosec A Cosec A + 1 Cosec A ⇒ Cosec A - 1Cosec A + 1 So, LHS = RHS ( Hence proved ) 2 View Full Answer