shape of NH4Cl?(by hybridization)

Dear student

NH₄Cl exists as NH₄⁺Cl^-. So hybridisation of N in NH₄⁺ is calculated by stating that there are 5 valence electrons in Nitrogen and as the species has a +ve charge, 4 electrons remain at the central atom. These 4 electrons bond to four hydrogens forming four bond pairs. Thus the hybridisation is sp³




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