shape of NH4Cl?(by hybridization)

Dear student

NH4Cl exists as NH4+Cl-. So hybridisation of N in NH4+ is calculated by stating that there are 5 valence electrons in Nitrogen and as the species has a +ve charge, 4 electrons remain at the central atom. These 4 electrons bond to four hydrogens forming four bond pairs. Thus the hybridisation is sp3


  • 0
What are you looking for?