Show that of all line segments drawn from the given point not on it, the perpendicular line segment is the shortest.

Hi!

Given:

*l*is a straight line and A is a point not lying on*l*. AB⊥*l*and C is a point on*l*.To prove: AB < AC

Proof: In ∆ABC,

∠B = 90°

Since, C can lie anywhere on

*l*(other than M)So, AB is the shortest of all line segments drawn from A to

*l*.Cheers!

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