Show that of all line segments drawn from the given point not on it, the perpendicular line segment is the shortest.
Hi!
Given: l is a straight line and A is a point not lying on l. AB⊥ l and C is a point on l.
To prove: AB < AC
Proof: In ∆ABC,
∠B = 90°
Since, C can lie anywhere on l (other than M)
So, AB is the shortest of all line segments drawn from A to l.
Cheers!