Show that the middle term in the expansion of (1+x)^2n is x^n 1 3 5----(2n-1)/n! 2^n where - Maths - Binomial Theorem

Question

Show that the middle term in the expansion of (1+x)^2n is x^n 1
3 5----(2n-1)/n! 2^n where 'n' is a +ve integer

Aakash Sharma · Accepted Answer

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Show that the middle term in the expansion of (1+x)^2n is x^n . 1.3..5----(2n-1)/n! 2^n where 'n' is a +ve integer