show that the points A(1,2), B(-1,-16) and C(0,-7) lie on the graph of the linear equation y=9x-7.

If the points A(1, 2), B(–1, –16) and C(0, –7) lie on the graph of the linear equation *y* = 9*x *– 7 then the these points should satisfy the equation of the given line.

Let us check it:

For point A(1, 2),

Here, *x* = 1 and *y* = 2, therefore

*y* = 9*x *– 7

⇒ 2 = 9 (1)* *– 7

⇒ 2 = 2

Thus, point A lies on the given line.

For point B(–1, –16)

Here, *x* = –1 and *y* = –16, therefore

*y* = 9*x *– 7

⇒ –16 = 9 (–1)* *– 7

⇒ –16 = –16

Thus, point B lies on the given line.

For point C(0, –7),

Here, *x* = 0 and *y* = –7, therefore

*y* = 9*x *– 7

⇒ –7 = 9 (0)* *– 7

⇒ –7 =* *–7

Thus, point C lies on the given line.

Hence, all three points A, B and C lie on the line *y* = 9*x *– 7.

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