Sides BC,CA and BA of a triangle ABC are produced to D,Q,P respectively. If angle ACD=100 and angle QAP=35, find all the angles of the triangle.


QAP=BAC=35°    Vertically opposite anglesACD=ABC+BAC    Exterior angle100°=ABC+35°ABC=65°ABC+BAC+ACB=180°     Angle sum property65°+35°+ACB=180°ACB=80°.

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