simplify (2x-y+z)^2-(2x+y-z)^2

As we know that, {(a + b + c)}^{2} = a^{2} + b^{2} + c^{2} + 2 ab + 2 bc + 2 ca {(2 x - y + z)}^{2} - {(2 x + y - z)}^{2} = 4 x^{2} + y^{2} + z^{2} - 4 xy - 2 yz + 4 xz - (4 x^{2} + y^{2} + z^{2} + 4 xy - 2 yz - 4 xz) = 4 x^{2} + y^{2} + z^{2} - 4 xy - 2 yz + 4 xz - 4 x^{2} - y^{2} - z^{2} - 4 xy + 2 yz + 4 xz = - 8 xy + 8 xz = 8 x (z - y)