sin 105 degree +cos 105 degree =cos 45 degree
To prove : sin 105° + cos 105° = cos 45°
LHS = sin 105° + cos 105°
= cos 15° – sin 15° [sin (90° + θ) = cos θ, cos (90° + θ) = – sin θ]
Finding sin 15° and cos 15°:
sin 105 degree +cos 105 degree =cos 45 degree
To prove : sin 105° + cos 105° = cos 45°
LHS = sin 105° + cos 105°
= cos 15° – sin 15° [sin (90° + θ) = cos θ, cos (90° + θ) = – sin θ]
Finding sin 15° and cos 15°: