sir my question is an activity and that activity is-
ask students to write 3-digit number. choose any student from from the room at random. what probability that the number written by her/him is divisible by 3? Remember that a number is divisible by 3, is the sum of it's digit is divisible by 3.
So sir/madam please give the answer of this activity or how can we perform this activity............

Answer :

We know Probability  P ( E  ) = Total number of desired events n ( E)Total number of events n ( S)

We know ,

All three digits numbers are  900  , So

n  (  S ) =   900 

And

we know 9993 - 993  =  333 - 33  = 300 digits divisible by  3 ( In between 100 and 999 )

So,

n (  E ) =  300 

So ,

Probability that the number written by her/him is divisible by 3 = 300900 =  13                                       ( Ans )

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