solubility of AlCl in water at 25 is 1.06*10^-5 calculate the solubility product of AlCl at this temperature?pls answer fast
Dear student
Please find the solution to the asked query:
Solubility of AgCl =[Ag+][Cl-] =1.06 x 10-5
AgCl(s)---> Ag+ +Cl-
Ksp = [Ag+][Cl-]/[AgCl] =[Ag+][Cl-]. as [AgCl] =1 as it is a solid
So
Ksp = [1.06 x 10-5]2 = 1.1236 x 10-10
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards
Please find the solution to the asked query:
Solubility of AgCl =[Ag+][Cl-] =1.06 x 10-5
AgCl(s)---> Ag+ +Cl-
Ksp = [Ag+][Cl-]/[AgCl] =[Ag+][Cl-]. as [AgCl] =1 as it is a solid
So
Ksp = [1.06 x 10-5]2 = 1.1236 x 10-10
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards