Dear student, If the object distance is U and image distance is V Then from the magnification equation, M=hi/ho=-V/U â‡’ -V/U=1/6â‡’ V=-U/6 â‡’ V=-(-0 12)/6 â‡’ V=0 02m= 2cm U= -12cm Therefore, the focal length of the mirror is, 1/F=1/U+1/V â‡’ 1/F=1/(-12) + 1/2â‡’ 1F= 2-12/-24 1/F= 10/24â‡’ F=24/10 cmâ‡’ F=2 4 cm Thanks and regards

Solve 14 one

Dear student, If the object distance is U and image distance is V. Then from the magnification equation, M=hi/ho=-V/U ⇒ -V/U=1/6⇒ V=-U/6 ⇒ V=-(-0.12)/6 ⇒ V=0.02m= 2cm. U= -12cm Therefore, the focal length of the mirror is, 1/F=1/U+1/V ⇒ 1/F=1/(-12) + 1/2⇒ 1F= 2-12/-24 1/F= 10/24⇒ F=24/10 cm⇒ F=2.4 cm Thanks and regards

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