Solve 2nd part

Dear Student ,

ii 32x÷2y+1 = 1, 164-x2-8y = 032x22y+1=1              using a=a12 ,abc=abc  abac=ab-c25x22y+1=1 25x2-y-1=20On comparing we get, 5x2-y-1=05x-2y-2=05x-2y=2              ...........1Now,164-x2-8y=0168-x2-8y = 0216-2x-23y=023y=216-2xComparing we get, 3y=16-2x2x+3y=16         .........2multiplying equation 1 by 3 and 2 by 2,we have15x-6y=6        .........34x+6y=32        .........4Adding equation 3 and 419x=38x=2substituting value of x in equation 1we get, 52-2y=22y=8y=4Thus value of x=2 and y=4

Regards

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