Solve 2x^2+2x-3=0 gicing your answer correct to the two decimal place

2x2+2x-3=0Use quadritic formulax=-2±4+4×3×22×2x=-2±4+242×2x=-2±282×2x=-2±272×2x=-1±72x=-1+72, -1-727=2.645x=-1+2.6452, -1-2.6452x=0.8225, -1.8225Round off to two decimal placesx=0.82, -1.82

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