solve 3x+5y=12 and 5x+4y=14 by elimination method

try multiplying both the equations with 14 in equation 1 and 12 in equation 2
 

i tried but not get the answer

Multiply 1 equation by 5 and 2 equation by 3 to make the coefficients of x same and then carry on the method of solving.

can you please do the solution

below is the answer

Here, 3x + 5y = 12_----(1)
          5x + 4y = 14_----(2)
Now, on multiplication of equations (1) and (2) with 5 and 3, we obtain:
          15x + 25y = 60_----(3) 
          15x + 12y = 42_----(4) 
Now, on Subtracting equation (4) from (30, we obtain the following result
                             13y  =  18
                    =>        y =  (18 / 13)
Now, on substituting the value of y in equation (1), we get:
             3x + 5(18/13) = 12
        =>    3x  =  12 - (90/13)
        =>     x  =   66 / (13*3)
        =>     x  =   22 / 13

thanks for help me