solve 4/x-1 ≤ 3 ≤ 6/x+1 ; x>0 Share with your friends Share 0 Manbar Singh answered this 4x-1 ≤3⇒4x-1 -3≤0⇒-3x+7x-1≤0⇒3x-7x-1≥0⇒x∈-∞, 1∪[7/3, ∞) .....1and 6x+1 ≥ 3⇒6x+1 - 3 ≥ 0⇒-3x+3x+1 ≥ 0⇒3x-3x+1 ≤ 0 ⇒x∈(-1, 1] ......2From 1 and 2, we getx ∈0, 1 0 View Full Answer
