Solve for x: 16x2-20(a+b)+(6a2​+13ab+6b2)=0

Dear student
we have,16x2-20a+bx+6a2+13ab+6b2=0x=20a+b±20(a+b)2-4166a2+13ab+6b232x=20a+b±400a2+400b2+800ab-384a2-832ab-384b232x=20a+b±16a2-32ab+16b232x=20a+b±4a2-2ab+b232x=5a+b±a-b8x=5a+b+a-b8 or x=5a+b-a-b8x=6a+4b8 or x=4a+6b8x=3a+2b4 or x=2a+3b4
Regards

  • 4
opps i forgot to put x after 20(a+b).
So the equation should be 16x2​-20(a+b)x+(6a2​+13ab+6b2​) = 0
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cannot understand the question
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s u c k my c o c k
 
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What are you looking for?