Solve for x. Q.4. Solve for x : ${\mathrm{tan}}^{-1}\left(\frac{1-x}{1+x}\right)=\frac{1}{2}{\mathrm{tan}}^{-1}x,x0$ Share with your friends Share 0 Rupal Sahu answered this Please find this answer 3 View Full Answer N I S H I D H A . answered this Thanks a lot Rashi. :D 0 Reena answered this But -1/root3 will get rejected due to given condition x>0 1 N I S H I D H A . answered this Thnkx Sachit. ^_^ 0