Solve for x - tan^-1 (x+1) + tan^-1 (x-1) = tan^-1 8/31

LOL 

- lizil

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 Yeah I'm pretty sure she appreciates my answer :))

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 Apply tan to both sides: 

tan [tan^-1 (x+1) +tan^-1 (x-1)] = tan(tan^-1 8/31) 
[(x+1) + (x-1)] / [1- (x+1)(x-1)] = 8/31

 by using tan(a+b) formula. 
==> 2x/ (2 - x^2) = 8/31.
==>16 - 8x^2 = 62x
==> 4x^2 + 31x - 8 = 0
==> (4x - 1)(x + 8) = 0.
==> x = 1/4 or -8.
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i agree with the Apurva
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X=1/4 is only possible solution
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F**k
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Only 1/4 be the possible solution for this equation
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Here's the easiest ans

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YO
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Tan inverse( X + 1) + tan inverse(x - 1)= tan inverse 8 /31

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Solution

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Solve the equation

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What are you looking for?