Solve Q no. 8 pls as soon as possible.

Dear student

In AOB and OBCOA=OCOB=OB   [common]AOB=BOC=60°AOBBOC    [By SAS rule]AO=BO,AB=BC   [By CPCT]In AOBAO=BOOAB=ABO   [Angles opposite to equal sides are equal]In AOB,by angle sum property of triangleAOB+OAB+ABO=180°2OAB=180°-60°OAB=ABO=60°So, AOB is an equlilateral triangle.AB=OA=OB=14cmSo, radius of circle=14cmArea of circle=πr2=227×14×14=616cm2
Regards

  • 0
it is a  NCERT sum..pls go through your textbook.
  • -4
Pi x (R)(R) 22/7 x 14 x 14 ​
= 44 x 14 = 616 square centimeter  
  • 2
hope this helps.

  • 4
done

  • 1
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