Solve Q no. 8 pls as soon as possible. Share with your friends Share 0 Lovina Kansal answered this Dear student In △AOB and OBCOA=OCOB=OB [common]∠AOB=∠BOC=60°△AOB≅△BOC [By SAS rule]⇒AO=BO,AB=BC [By CPCT]In △AOBAO=BO⇒∠OAB=∠ABO [Angles opposite to equal sides are equal]In △AOB,by angle sum property of triangle∠AOB+∠OAB+∠ABO=180°2∠OAB=180°-60°∠OAB=∠ABO=60°So, △AOB is an equlilateral triangle.⇒AB=OA=OB=14cmSo, radius of circle=14cmArea of circle=πr2=227×14×14=616cm2 Regards 0 View Full Answer Akshaya Macharla answered this it is a NCERT sum..pls go through your textbook. -4 Athithya Narayanan answered this Pi x (R)(R) 22/7 x 14 x 14 = 44 x 14 = 616 square centimeter 2 Khushi Dhankhar answered this hope this helps. 4 Nitish Kapoor answered this done 1