# Solve the 8C question no.2

$2x+\frac{x}{2}=20\phantom{\rule{0ex}{0ex}}\frac{4x+x}{2}=20\phantom{\rule{0ex}{0ex}}5x=40\phantom{\rule{0ex}{0ex}}x=\frac{40}{5}=8$

Regards!

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$2x+\frac{x}{2}=20\phantom{\rule{0ex}{0ex}}\frac{4x+x}{2}=20\phantom{\rule{0ex}{0ex}}5x=40\phantom{\rule{0ex}{0ex}}x=\frac{40}{5}=8$

Regards!

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