Solve the following please.

Solution,
Given, the rod is in equilibrium.
For translational equilibrium:
R1+R2=W ...........(1)
For rotational equilibrium about the centre of the rod:
moment of R1=moment of R2l2×R1=l2×R2R1=R2 .......(2)Thus, putting R1=R2 in eq. (1), we getR1=R2=W2

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