Solve the inequality - 1< x2+3x+4 / x2+4x+5 >2 Share with your friends Share 1 Anuradha Sharma answered this Assuming the question as it is, -1<x2+3x+4x2+4x+5>2 Now either, -1<x2+3x+4x2+4x+5x2+3x+4x2+4x+5+1>0x2+3x+4+x2+4x+5x2+4x+5>02x2+7x+9x2+4x+5>0....1Now for x2+4x+5=0 D = b2-4ac= 16-20 = -4 So roots will be imaginary and x2+4x+5>0 , so we can cross-multiply in equation 1, 2x2+7x+9>0......2Now D = 49-72 <0 So 2x2+7x+9 have imaginary root and will always be greater than 0 so equation 2 will always holds true for all the values of x. x∈R.....3Now Taking second inequality, x2+3x+4x2+4x+5>2 or x2+3x+4x2+4x+5-2>0 or x2+3x+4-2x2-8x-10x2+4x+5>0-x2-5x-6x2+4x+5>0 or x2+5x+6x2+4x+5<0Again x2+4x+5>0 so we can cross multiply, x2+5x+6<0 x+2x+3<0 or x ∈-3,-2......4So intersection of equation 3 and 4 is, x ∈-3,-2 Answer -1 View Full Answer Yasra Fatema answered this plzzzzz ans my ques fast plzzzzzzzz /........... 0
