Solve this:

103.  If the nth term in a sequence of numbers a 0 ,   a 1 ,   a 2 ,   . . . . . . ,   a n  is defined to equal 2n + 1, then what is the numerical difference between the 5th and 6th terms in the sequence? 

A.  1                                                            B.  2
C.  4                                                            D.  5

Dear Student,
Please find below the solution to the asked query:

nth term of sequence is given byan=2n+1a5=2×5+1=11a6=2×6+1=13a6-a5=13-11=2

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Two
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hi yayati
anser is
2,put value of n=2 and you ill get 5th term i.e.11 and value of  n=6, i.e. =13 so difference is 13-11=2













 
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Actual reason is
By seeing the given sequence the first term stars with a with power 0 (a0)it means that fifth term in that sequence will be a with the power 4 (a4)..
So to find fifth term keep the value of n as 4
So fifth term will be 9
And to find 6th term keep the value of n as 5
So 6th term is 11
And numerical difference is 11-9=2
So your option will be B
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