Solve this:

103.  If the nth term in a sequence of numbers a 0 ,   a 1 ,   a 2 ,   . . . . . . ,   a n  is defined to equal 2n + 1, then what is the numerical difference between the 5th and 6th terms in the sequence? 

A.  1                                                            B.  2
C.  4                                                            D.  5

Dear Student,
Please find below the solution to the asked query:

nth term of sequence is given byan=2n+1a5=2×5+1=11a6=2×6+1=13a6-a5=13-11=2

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

  • 0
  • 0
hi yayati
anser is
2,put value of n=2 and you ill get 5th term i.e.11 and value of  n=6, i.e. =13 so difference is 13-11=2

  • 1
Actual reason is
By seeing the given sequence the first term stars with a with power 0 (a0)it means that fifth term in that sequence will be a with the power 4 (a4)..
So to find fifth term keep the value of n as 4
So fifth term will be 9
And to find 6th term keep the value of n as 5
So 6th term is 11
And numerical difference is 11-9=2
So your option will be B
  • 0
What are you looking for?