#
Solve this:

**103.** If the n^{th} term in a sequence of numbers ${a}^{0},{a}^{1},{a}^{2},......,{a}^{n}$ is defined to equal 2n + 1, then what is the numerical difference between the 5th and 6th terms in the sequence?

A. 1 B. 2

C. 4 D. 5

Please find below the solution to the asked query:

${\mathrm{n}}^{\mathrm{th}}\mathrm{term}\mathrm{of}\mathrm{sequence}\mathrm{is}\mathrm{given}\mathrm{by}\phantom{\rule{0ex}{0ex}}{\mathrm{a}}_{\mathrm{n}}=2\mathrm{n}+1\phantom{\rule{0ex}{0ex}}{\mathrm{a}}_{5}=2\times 5+1=11\phantom{\rule{0ex}{0ex}}{\mathrm{a}}_{6}=2\times 6+1=13\phantom{\rule{0ex}{0ex}}{\mathrm{a}}_{6}-{\mathrm{a}}_{5}=13-11=2$

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

Regards

**
**