Solve this:
14. In an electromagnetic wave, the oscillating electric field having a frequency of 3*1010 Hz and an amplitude of 30 V/ m propagates in the positive x-direction.

(i) What is the wave length of the electromagnetic-wave?
(ii) Write down the expression to represent the corresponding magnetic field.

Ans .   10 - 2 m ,   B = 10 - 7 T sin 6 π × 10 10 t - 200 πx k ^

Dear Student,


f=3*1010 Hz, E0=30 V/mi.wavelength=cf=3*1083*1010=10-2 m ii.B0=303*108=10-7 TB=10-7sin6π*1010tRegards

  • -1
What are you looking for?