Solve this: 24 . W h i c h g i v e s o n l y 25 % m o l e o f A g C l , w h e n r e a c t s w i t h A g N O 3 : - ( 1 ) P t C l 2 . 4 N H 3 ( 2 ) P t C l 4 . 5 N H 3 ( 3 ) P t C l 4 . 4 N H 3 ( 4 ) P t C l 4 . 3 N H 3 Share with your friends Share 29 Ashish Khanna answered this Dear Student These are the general chemical formula of the coordination compound. In reality, PtCl4.4NH3 exist as [Pt(NH3)4Cl2]Cl2 and PtCl4.3NH3 exist as [Pt(NH3)3Cl3]ClNow, [Pt(NH3)4Cl2]Cl2 + 2AgNO3 → 2AgCl 1 mol 2 mol while,[Pt(NH3)3Cl3]Cl + AgNO3 → AgCl 1 mol 1 mol1 mol of [Pt(NH3)4Cl2]Cl2 gives 2 mol of AgClwhile 1 mol of [Pt(NH3)4Cl3]Cl gives 1 mol of AgCl.PtCl4.3NH3 or [Pt(NH3)3Cl3]Cl gives only 25% of AgCl as we can see than here 4 Cl are present, but only 1 mol of AgCl is obtained i.e. 14×100=25%. This is because here the 3 Cl atoms are inside the coordination sphere while 1 Cl is outside, therefore 1 Cl is only available for AgNO3.In PtCl4.4NH3 or [Pt(NH3)4Cl2]Cl2, 4 Cl are present and 2 mol of AgCl is obtained, i.e. here 50% mole of AgCl is formed. So, the correct option is (4) Regards 6 View Full Answer