Solve this: 31. A sample pendulum executing SHM has a period T and amplitude A. Its peed, when at a distance A/4 is a πA 15 2 T b πA 15 T c πA 2 T d πA T Share with your friends Share 0 Shobhit Mittal answered this Dear Student,speed at a distance A/4 from the center maximum speed at the center is Aωω=2πTvmax=2πATx=Asinωtx=A4 the time is A4=Asinωtsinωt=14cosπ2-ωt=14t=1ωπ2-cos-14speed at t=1ωπ2-cos-14v=Aωcosωtv=Aωcosω1ωπ2-cos-14=Aωcosπ2-cos-14v=Aωsincos-14cosθ=14,sinθ=154v=A2πT*154=AπT*152option aregards 0 View Full Answer