Solve this:

31. A sample pendulum executing SHM has a period T and amplitude A. Its peed, when at a distance A/4 is

a   πA 15 2 T b   πA 15 T c   πA 2 T d   πA T


 

Dear Student,speed at a distance A/4 from the center maximum speed at the center is Aωω=2πTvmax=2πATx=Asinωtx=A4 the time is A4=Asinωtsinωt=14cosπ2-ωt=14t=1ωπ2-cos-14speed at t=1ωπ2-cos-14v=Aωcosωtv=Aωcosω1ωπ2-cos-14=Aωcosπ2-cos-14v=Aωsincos-14cosθ=14,sinθ=154v=A2πT*154=T*152option aregards

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