Solve this:
A solid spherical ball of the metal is divided into two hemispheres & joined as shown in figure. The solid is placed in the cylindrical tub full of water in such a way that the whole solid is submerged in water. The radius & height of cylindrical tub are 4 cm & 11 cm respectively & the radius of spherical ball is 3 cm. Find the volume of water left in the cylindrical tub.
4/3πr3 = 12π cm3(vol.of 2 hemispheres)
πr2h=176π cm3(vol. of cylinder)
vol. displaced = vol. of 2 hemisphere
=> vol.of water remaining is
vol.of cylinder-vol. of 2 hemisphere
= 176π-12π
=154π = 484 cm3
ans: the remaining vol. of water in the cylinder is 484 cm3
πr2h=176π cm3(vol. of cylinder)
vol. displaced = vol. of 2 hemisphere
=> vol.of water remaining is
vol.of cylinder-vol. of 2 hemisphere
= 176π-12π
=154π = 484 cm3
ans: the remaining vol. of water in the cylinder is 484 cm3