#
Solve this:

A solid spherical ball of the metal is divided into two hemispheres & joined as shown in figure. The solid is placed in the cylindrical tub full of water in such a way that the whole solid is submerged in water. The radius & height of cylindrical tub are 4 cm & 11 cm respectively & the radius of spherical ball is 3 cm. Find the volume of water left in the cylindrical tub.

^{3 }= 12π cm

^{3}(vol.of 2 hemispheres)

πr

^{2}h=176π cm

^{3}(vol. of cylinder)

vol. displaced = vol. of 2 hemisphere

=> vol.of water remaining is

vol.of cylinder-vol. of 2 hemisphere

= 176π-12π

=154π = 484 cm3

ans: the remaining vol. of water in the cylinder is 484 cm

^{3}