Solve this : Answer is option (3) 20 . If y = Ax B 2 + x 2 3 2 ; where A and B are positive constants ; then value of y is maximum a x equal to : ( 1 ) Zero ( 2 ) B ( 3 ) ± B 2 ( 4 ) A B Share with your friends Share 0 Koka Sri Lakshmi Divya Sai answered this Dear Student Giveny=AxB2+x232Now to get the maximum value we have to find dydx⇒dydx=ddxAxB2+x232 =B2+x232ddxAx-AxddxB2+x232B2+x2322 =B2+x232A-Ax32B2+x232-1.ddxB2+x2B2+x23 =AB2+x232-Ax32B2+x2122xB2+x23 =AB2+x232-3Ax2B2+x212B2+x23Now to get a maximum value dydx=0⇒AB2+x232-3Ax2B2+x212B2+x23=0⇒AB2+x212B2+x2-3x2=0⇒B2+x2-3x2=0⇒B2-2x2=0⇒2x2=B2⇒x=±B2So, y value will bw maximum at x=±B2 Regards 0 View Full Answer