Solution:2H2O→2H2+O2(a) Volume of O2 produced is half the volume of H2 If 2500 cm3 of H2 is produced, 25002cm3=1250 cm3(b) At constant temperature, P1V1=P2V2 ⇒P1×2500=52P1×V2 ⇒V2=1000 cm3H2 gas occupies 1000 cm3 volume(c) At constant pressure, V1T1=V2T2 1000T1=2500T2 T2=2 5T1Temperature of gas must be increased by 2 5 times

Solve this please.

S o l u t i o n : 2 H_{2} O \overset{}{\to} 2 H_{2} + O_{2} (a) V o l u m e o f O_{2} p r o d u c e d i s h a l f t h e v o l u m e o f H_{2} I f 2500 c m^{3} o f H_{2} i s p r o d u c e d, \frac{2500}{2} c m^{3} = 1250 c m^{3} (b) A t c o n s \tan t t e m p e r a t u r e, P_{1} V_{1} = P_{2} V_{2} \Rightarrow P_{1} \times 2500 = \frac{5}{2} P_{1} \times V_{2} \Rightarrow V_{2} = 1000 c m^{3} H_{2} g a s o c c u p i e s 1000 c m^{3} v o l u m e (c) A t c o n s \tan t p r e s s u r e, \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \frac{1000}{T_{1}} = \frac{2500}{T_{2}} T_{2} = 2.5 T_{1} T e m p e r a t u r e o f g a s m u s t b e i n c r e a s e d b y 2.5 t i m e s .

View Full Answer