# Solve this pls....

Suppose total current flowing in the circuit is I, then the current passing through resistance R_{1} will be I_{1,} current passing through resistance R_{2} will be I_{2} and current passing through resistance R_{3}will be I_{3.}

Total current =I=I_{1}+I_{2}+I_{3}

Let resultant resistance of this parallel combination is R. By applying the Ohm's law to the whole circuit, we get that

I=V/R

Since the potential difference across all the resistances is same, so applying the Ohm's law to each resistance we get that

I_{1}=V/R_{1}

I_{2}=V/R_{2}

I_{3}=V/R_{3}

Putting these eqs. in the above one, we get

V/R=V/R_{1}+V/R_{2}+ V/R_{3}

1/R=1/R_{1}+1/R_{2}+ 1/R_{3}

If three resistance are connected in parallel, then the resultant resistance will be

1/R=1/R_{1}+1/R_{2}+ 1/R_{3}

As potential difference across the circuit as well as across each resistor will be same so voltmeter is connected through main circuit across resistors.

As current in the circuit is required so ammeter also need to connect near battery.

Regards

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