# Solve this Q.10. The following table shows the blood group of 30 students of a class. One student of the class is chosen at random. What is the probability that the chosen student has a blood group (i) A (ii) AB

Total number of students = 30
(i) Number of students having blood group A = 9
Probability of getting A =9/30 =3/10

and,
(ii) Number of students having blood group AB = 3

Hence, required probability of getting blood group AB,

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Probability of getting A =  possible outcomes/total outcomes = 9/30 = 3/10
Probability of getting AB = 9+7/30 = 16/30 = 8/15

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