Solve this.
Q.135. If a1 , a2, a3 , .... is an arithmetic progression with common difference 1 and  i = 1 98   a 1  = 137,  then the value of  a2 + a4 + a6 + ......+ a98 is 
(1) 67
(2) 83 
(3) 93
(4) 98

Dear student
We have,a1,a2,a3,...a98 in an A.P with common difference 1and ai =137i=198Since from 1 to 98 there are 49 odd numbers, each 1 less than the following even termSo, 2a2+a4+...+a98-49=1372a2+a4+...+a98=186a2+a4+...+a98=93
Regards

  • 14
no idea
 
  • -16
sorry
  • -17
What are you looking for?