Solve this. Q.135. If a1 , a2, a3 , .... is an arithmetic progression with common difference 1 and ∑ i = 1 98 a 1 = 137, then the value of a2 + a4 + a6 + ......+ a98 is (1) 67 (2) 83 (3) 93 (4) 98 Share with your friends Share 11 Lovina Kansal answered this Dear student We have,a1,a2,a3,...a98 in an A.P with common difference 1and ∑ai =137i=198Since from 1 to 98 there are 49 odd numbers, each 1 less than the following even termSo, 2a2+a4+...+a98-49=137⇒2a2+a4+...+a98=186⇒a2+a4+...+a98=93 Regards 14 View Full Answer Shivam Pandey answered this no idea -16 Abhi answered this sorry -17