Solve this:
Q.20. A particle of mass 80 units is moving with a uniform speed v = 4 2 units in XY plane, along a line y = x + 5. The magnitude of the angular momentum of the particle about the origin is
1) 1600 units
2) 160 2 units
3) 152 2 units
4) 16 2 units

Dear student,
The particle is moving in a circle,
y=x+5or x-y+5=0From this equationThe perpendicular distance will be(r) =52Angular momentum L=mvrL=80×42×52L=1600units
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