Solve this: Q) Factorise: ${x}^{4}-14{x}^{2}+1$ Share with your friends Share 1 Shweta Singh answered this wait 0 View Full Answer Shyam S.k. answered this x^{4 }-14x^{2 }+1 =x^{4 }+2x^{2 }+1-16x^{2 } [-14-2=16] =(x^{2 }+1)^{2 }-(4x)^{2 } [a^{2 }+2ab+b^{2 }] =(x^{2 }+1+4x)(x^{2 }+1-4x) [a^{2 }-b^{2 }=(a+b)(a-b) 2 Sandeep answered this here is your answer 5 Somesh answered this Please find this answer -1 Donald answered this Jggjgfggggggyyy 2 Ishjyot Kaur answered this hhjjj 0 Poonam Yadav answered this Please send the photo again 0 Ansh H Mehta answered this x4?-14x?2?+1 =x4?+2x2?+1-16x2?? ? ? ? ? [-14-2=16] =(x2?+1)2?-(4x)2?? ? ? ? ? [a2?+2ab+b2?] =(x2?+1+4x)(x2?+1-4x)? ? ? ? ? [a2?-b2?=(a+b)(a-b) -1 Devansh Trivedi answered this Sorry i dont know this 0 Harsh Rai answered this Answer is here 1 Guddanti Nikhil Srinivas answered this x4 - 14 x 2 + 1 X4 - 28 + 1 (X4 - 28) + 1 4(x - 7) + 1 0 Sanket Kumar answered this Here is the solution, hope it might help you 0 Nuthan Baskar answered this x^{4 }-14x^{2 }+1 =x^{4 }+2x^{2 }+1-16x^{2 } [-14-2=16] =(x^{2 }+1)^{2 }-(4x)^{2 } [a^{2 }+2ab+b^{2 }] =(x^{2 }+1+4x)(x^{2 }+1-4x) [a^{2 }-b^{2 }=(a+b)(a-b) 1 Krishna Kushwaha answered this This is question p(x)=x?-14x?+1 Ans is p(x)= x?-7x?-7x?+1 =x?(x?-7)-1(7x?-1) = 0