Solve this: Q.(h) For de-excitation of electrons from n = 5 to n = 2 possible number of spectral lines emitted will be (1)10 (2) 6 (3) 4 (4) 8 Share with your friends Share 0 Sakshi Kanwar answered this Dear Student For de excitation of electrons the possible no. of spectral lines are(n2-n1)(n2-n1-1)=(5-2)(5-2-1)=6Option 2 is correct. Hope this information will clear your doubts about topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible. Regards 0 View Full Answer