Solve this: Q Vapour pressure of water is 360 mm Hg, how much urea should be added to 200 - Chemistry - Solutions

Question

Solve this:
Q Vapour pressure of water is 360 mm Hg, how much urea should be
added to 200 mL water to reduce its vapour pressure by 0 5 %?
(Molecular wt of urea = 60)

Ashwini Kumar Mishra · Accepted Answer

Dear student ,
P0 = 360 mmHg and Ps = 99 5 % of 360 = 358 2
mm Hg
by Raoult's law ; P0 - Ps / Ps = n
/N or w M / W m
360 - 358 2 / 358 2 = w × 18 / 200 × 60 ( as density of
water = 1 gm /ml )
w = 3 33 gm
Regards

Solve this: Q. Vapour pressure of water is 360 mm Hg, how much urea should be added to 200 mL water to reduce its vapour pressure by 0.5 %? (Molecular wt. of urea = 60)

Solve this:
Q. Vapour pressure of water is 360 mm Hg, how much urea should be added to 200 mL water to reduce its vapour pressure by 0.5 %? (Molecular wt. of urea = 60)