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Dear Student,
Please find below the solution to the asked query:
Given : Parking charges for vehicles in a parking is Rs. 20 for first two hour and Rs . 10 for subsequent
And total parking charges = y
So,
y = 20 + 10 ( x - 2 ) ,
y = 20 + 10 x - 20 ,
y = 10 x ( Ans )
We form a table for above equation for different values of ' x ' and ' y ' , As :
Now we draw required graph from above points , As :
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Given : Parking charges for vehicles in a parking is Rs. 20 for first two hour and Rs . 10 for subsequent
And total parking charges = y
So,
y = 20 + 10 ( x - 2 ) ,
y = 20 + 10 x - 20 ,
y = 10 x ( Ans )
We form a table for above equation for different values of ' x ' and ' y ' , As :
y = 10 x | |
x ( Given : x 2 ) | y |
2 | 20 |
4 | 40 |
5 | 50 |
8 | 80 |
10 | 10 |
Now we draw required graph from above points , As :
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards