Solve this:

x = -12, y = 7, z = 5 
  x3+y3+z3 = 3xyz when x+y+z = 0.
  x+y+z = -12 + 7 + 5 = -12+12 = 0
  x3+y3+z3 = 3xyz
                  = 3*-12*7*5
                  = -36*35
                = -1260


x = 28, y = -15, z = -13
x3+y3+z3 = 3xyz when x+y+z = 0.
x+y+z = 28 + (-15) + (-13) = 28 - 28 = 0
x3+y3+z3 = 3xyz
                = 3*28*-15*-13
                = 84*195
                = 16,380

  • 11
x³+y³+z³=3xyz when x+y+z=0 (-12)³+7³+5³ 3(-12)(7)(5) =-1260
  • 5
x=-12,y=7,z=5 x+y+z=-12+7+5 =-12+12 =0 ie.x^3+y^3+z^3=3xyz (-12)^3+(7)^3+(5)^3 =3×(-12)×7×5 =21×-60 =-1260
  • 3
x³+y³+ z³=3xyz where x+y+z=0 28³+(-13)³+(-15)³ 3(28)(-15)(-13) =18900
  • 1
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