3 The given equation is,5y - 2x = 14Now, we have to check whethere 4,3 is a solution of above equation or not If the given point satisfies the equation, then it is a solution otherwise not Put x = 4, y = 3 in the above equation, we getLHS = 5×3 - 2×4 = 15 - 8 = 7RHS = 14Simce, LHS≠RHS, so 4,3 does not satisfy the equation So, 4,3 is not a solution of the given equation 4 The given equation is, x + 2y = 7⇒x = 7 - 2yWhen y = 0, x = 7When y = 1; x = 5So, 7, 0 and 5, 1 are the 2 solutions of the given equation Kindly ask the remaining query in different thread

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(3) . The given equation is, 5 y - 2 x = 14 Now, we have to check whethere (4, 3) is a solution of above equation or not . If the given point satisfies the equation, then it is a solution otherwise not . Put x = 4, y = 3 in the above equation, we get LHS = 5 \times 3 - 2 \times 4 = 15 - 8 = 7 RHS = 14 Simce, LHS \neq RHS, so (4, 3) does not satisfy the equation . So, (4, 3) is not a solution of the given equation . (4) . The given equation is, x + 2 y = 7 \Rightarrow x = 7 - 2 y When y = 0, x = 7 When y = 1; x = 5 So, (7, 0) and (5, 1) are the 2 solutions of the given equation .

Kindly ask the remaining query in different thread.

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